0.01x^2-10x+200=0

Solution for 0.01x^2-10x+200=0 equation:

0.01x^2-10x+200=0

a = 0.01; b = -10; c = +200;
Δ = b2-4ac
Δ = -102-4·0.01·200
Δ = 92
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{92}=\sqrt{4*23}=\sqrt{4}*\sqrt{23}=2\sqrt{23}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2\sqrt{23}}{2*0.01}=\frac{10-2\sqrt{23}}{0.02}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2\sqrt{23}}{2*0.01}=\frac{10+2\sqrt{23}}{0.02}
$